Calculate ΔHᵣ° and ΔUᵣ° at 298.15 K for the following reactions: Part A 8NH₃(g) + 6NO₂(g) → 7N₂(g) + 12H₂O(g)
A) ΔHᵣ° = -163.2 kJ/mol, ΔUᵣ° = -170.8 kJ/mol
B) ΔHᵣ° = -170.8 kJ/mol, ΔUᵣ° = -163.2 kJ/mol
C) ΔHᵣ° = -163.2 kJ/mol, ΔUᵣ° = -189.6 kJ/mol
D) ΔHᵣ° = -189.6 kJ/mol, ΔUᵣ° = -163.2 kJ/mol