Solve the differential equation y³x*dy/dx=1 x. use the initial condition y(1) =5. express y⁴ in terms of x dy/dx = (1/(y³x)) * x

The initial condition is y(1) = 5.
a) y⁴ = (1/4)x² + 5⁴
b) y⁴ = (1/4)x² - 20
c) y⁴ = 5⁴ + (1/4)x²
d) y⁴ = 25 + (1/4)x²