0.45 M benzoic acid, C₆H₅COOH, and 0.10 M potassium benzoate C₆H₅COOK, with a Ka of C₆H₅COOH = 6.4 x 10⁻⁵. What is the pH for this buffer?
a. Calculate the initial concentration of benzoic acid (C₆H₅COOK) and potassium benzoate (C6H5COOK)
b. Set up an ICE table to calculate the equilibrium concentrations of C₆H₅COOH and C₆H₅COO⁻
c. Use the dissociation constant (Ka) to calculate the H+ concentration and then the pH
d. Final calculation: pH = -log[H⁺]