Find the solution to the following linear, homogeneous recurrence with constant coefficients:
aₙ =−4aₙ₋₁−4aₙ₋₂ −16aₙ₋₃ for n≥3 with initial conditions a0=5,a₁=12,a₂=−40. The solution is of the form:
an=(α+iβ)(ir)ⁿ +(α−iβ)(−ir)ⁿ +γsⁿ
for suitable integer constants α,β,γ,r,s. Note that the variable r in this problem doesn't represent a characteristic value. Find these constants and enter their values: