There is a chance that a bit transmitted through a digital transmission channel is received in error. Let X equal the number of bits in error in the next four bits transmitted. The possible values for X are {0, 1, 2, 3, 4}. Based on a model for the errors that is presented in the following section, probabilities for these values will be determined. P(X = 0) = 0.6561, P(X = 1) = 0.2916, P(X = 2) = 0.0486, P(X = 3) = 0.0036, P(X = 4) = 0.0001. The probability distribution of X is specified by the possible values along with the probability of each. Then the pmf of X is ________. f(x) = {0.6561, if x = 0 0.2916, if x = 1 0.0486, if x = 2 0.0036, if x = 3 0.0001, if x = 4. E(X) = V{X) = E(10X + 5) = V(10X + 5) = E( squareroot X) = Bonus! V( squareroot X) =