What is the full electron configuration of the Period 3 element with the following successive ionization energies (in kJ/mol):
IE1 = 738 IE2 = 1450 IE3 = 7732 IE4 = 10,539 IE5 = 13,628
The answer is: 1s^2 2s^2 2p^6 3s^2
I would like to know the steps to get this answer