The person is around 2 meters tall and the street light is only 8 meters above the ground. The rate at which the person is walking is 4/3
Step-by-step explanation:
We find the answer by using the equation ds/dt which equals to 4/9.
s represents the length of the shadow while x represents distant of shadow from the street light.
Hence we get x/6 = s/2 so dx/dt putting the values we get 6ds/2dt and the answer is 4/3