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15-12-2022
Mathematics

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Given \qquad m \angle ABDm∠ABDm, angle, A, B, D is a straight angle. \qquad m \angle CBD = 8x + 16^\circm∠CBD=8x+16 ∘ m, angle, C, B, D, equals, 8, x, plus, 16, degrees \qquad m \angle ABC = 6x - 60^\circm∠ABC=6x−60 ∘ m, angle, A, B, C, equals, 6, x, minus, 60, degrees Find m\angle ABCm∠ABCm, angle, A, B, C:

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