½ H₂(g) + ½ I₂(s) --> HI(g) ΔH= 26 kJ/mol
½ H₂(g) + ½ I₂(g) --> HI(g) ΔH= -5.0 kJ/mol
Based on the information above, what is the enthalpy change for the sublimation of iodine, represented by Iâ‚‚(s) --> Iâ‚‚(g)?
a) 15 kJ/mol
b) 21 kJ/mol
c) 31 kJ/mol
d) 42 kJ/mol
e) 62 kJ/mol