h(x) = x³ + ax² + bx + c the function h is defined above where a, b and c are integer constants.
If the zero of the function are -6 , 1 , and 3 what is the value of c?
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I would appreciate it if you also explain/show how to solve the equations (ex: -216 + 36a - 6b + c = 0) instead of just giving the answer so I can learn! Do I just divide it all by 6?