The block is slowly pulled from its equilibrium position to some position xịnit > 0 along the x axis. At time t = 0, the block is released with zero initial velocity. Constants I Periodic Table The goal is to determine the position of the block x (t) as a function of time in terms of w and xinit - Part A It is known that a general solution for the displacement from equilibrium of a harmonic oscillator is Using the general equation for x (t) given in the problem introduction, express the initial position of the block xinit terms of C, S, and w (Greek letter omega). in x(t) = C cos (wt)+S sin (wt), View Available Hint(s) where C, S, and w are constants. (Figure 2) Your task, therefore, is to determine the values of C and S in terms of w and xinit - Ηνα ΑΣφ ? a Figure xa Xb |X| Х.10п 2 of 3 Tinit = C cos (wt)+S sin (wt) +x Submit Previous Answers m X Incorrect; Try Again; 5 attempts remaining x(1) The correct answer does not depend on: S, wt. 18