Respuesta :

konrad509

[tex]\displaystylea_1=-2\\r=8\\a_n=8a_{n-1}\\\\\left \{ {{a_1=-2} \atop {a_n=8a_{n-1}}} \right.[/tex]

facundo3141592

Answer: The sequence is: An = -2*8^(n-1)

Step-by-step explanation:

 geometric sequence is of the form:

An = a*r^(n-1)

where can be any positive integer number.

here the first two numbers are -2 and -16, so we have that:

A1 = a*r^(0) = a = -2

now, we know that our sequence is of the form:

An = -2*r^(n-1)

now, for n= 2 we have that:

A2 = -2*r^(1) = -2*r = -16

r = -16/-2 = 8

now we have determinated our sequence:

An = -2*8^(n-1)

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